9. A Masterpiece and ...


Spielmann - Rubinstein [C90] St. Petersburg, 1909


1 e4 e5 2 Nf3 Nc6 3 Bb5 a6 4 Ba4 Nf6 5 O-O Be7 6 Re1 b5 7 Bb3 d6 8 c3 Bg4 9 h3 Bh5 10 d3 O-O 11 Nbd2 d5 12 exd5 Nxd5 13 Nf1 Bf6 14 g4 Bg6 15 g5 Be7 16 Nxe5 Nxe5 17 Rxe5 Nb6 18 d4 Nd7 19 Re1 Bxg5 20 Bxg5 Qxg5+ 21 Qg4 Qd8 22 Ng3 Nf6 23 Qf3 Qd7 24 Kh2 a5 25 a3 Rab8 26 Re5 Rfe8 27 Rg1 b4 28 Rxa5 bxc3 29 Qxc3 Ne4 30 Nxe4 Rxe4 31 Rd5 Qe7 32 Rc5 Re2 33 Qg3 Qd6 34 Qxd6 cxd6 35 Rc7 Rxb2 36 Rgc1 Kf8 37 Bc2 Ra2 38 Bxg6 hxg6 39 R1c2 Rxc2 40 Rxc2


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Diagram 1: Position after 40 Rxc2, s. page 277 of Mark I. Dvoreckij, Die Endspieluniversität, Chessgate 2002


40...Ra8 41 Rc3 Ra4 42 Rd3


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Diagram 2: Position after 42 Rd3


42...Ke7 43 Kg3 Ke6 44 Kf3 Kd5 45 Ke2 g5 46 Rb3 f6 47 Ke3 Kc4 48 Rd3 d5 49 Kd2 Ra8 50 Kc2 Ra7 51 Kd2 Re7


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Diagram 3: Position after 51...Re7


52 Rc3+? Probably an absolute error. 52 a4! probably holds the ballance. It could follow:


52...Ra7 53 Ra3 Kb4 54 Ra1 Rxa4 55 Rc1 Ra7 (55...Ra5 56 Rc7 Ra6) 56 Rc5 Ra5 (56...Rd7) 57 Rc7 Ra2+ 58 Ke3 Ra3+ 59 Ke2 Rxh3 60 f3 Rh4 (60...Rh7 61 Rc5) 61 Ke3 g4 62 Rxg7 gxf3 63 Rb7+ Kc4 64 Rc7+ Kb3 65 Rc5 f2 (65...Re4+ 66 Kxf3 leads to a ballenced position: (=/=))66 Kxf2 Rxd4 67 Ke3 leads also to equality for White to move!


52...Kxd4 53 a4 Ra7 54 Ra3 Ra5 55 Ra1 Kc4 56 Ke3 d4+ 57 Kd2 Rf5 58 Ke1 Kb4 59 Ke2 Ka5 60 Ra3 Rf4 61 Ra2 Rh4 62 Kd3 Rxh3+ 63 Kxd4 Rh4+ 64 Kd3 Rxa4 65 Re2 f4 66 Ke3 Kb6 67 Rc2 Kb7 68 Rc1 Ra4 69 Rh1 Kc6 70 Rh7 Ra7 71 Ke4 Kd6 72 Kf5 g6+ 73 Kxg6 (7-pieces endgame: (+/+)) 73...Rxh7 74 Kxh7 Ke5 75 Kg6 g4 0-1


... Oops (incorrect) Splitting!


Let´s go back to the position after 42 Rd3, s. diagram 4. There is a pawn ending on the right side of the board, and a rook ending on the left side (In most cases pawns do not change sides. But rooks and kings normally do. But at the moment we don´t care about that!)


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Diagramm 4: Probably a (=/=)-position


Now Oops divides this position in two parts as shown in diagrams 5 and 6 (it does proof nothing, but it is nice to see!):


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Diagram 5: A (=/=)-position


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Diagram 6: A (-/+)-position


The 7-pieces database – Oops Zermelo-looking glas – gives the following results:


The position in diagram 5 is of type (=/=), i.e. neither side has - by perfect playing - not more than equality.


The position in diagram 6 is different: It is of type (–/+), i.e. Black is winning with or without the right to move.


If it is Black to move, he will finish the game 3 moves earlier compared to the case starting with White. The following moves sometimes look a little bit strange, but the white king wants to survive as long as possible!


1 Kg3 Ke7 2 Kf4 Ke6 3 Kg5 Ke5 4 Kg4 Ke4 5 f4 Kd4 6 Kh4 Kd3 7 Kg5 Ke3 8 Kg4 Ke4 9 Kg3 Kf5 10 Kf3 g5 11 fxg5 Kxg5 12 Kg3 g6 13 h4+ Kf5 14 Kf3 Ke5 15 Ke3 f5 16 Kd3 f4 17 Kc3 f3 18 Kd3 Kf4 19 Kd2 f2 20 Ke2 Kg3 21 h5 gxh5 22 Ke3 f1Q 23 Kd4 Qb5 24 Kc3 Qa4 25 Kd3 Kf3 26 Kc3 Ke3 27 Kb2 Kd3 28 Kb1 Kc3 29 Kc1 Qa1# 0:1


1...g5 2 Kg2 Ke7 3 Kh2 f6 4 Kg2 Ke6 5 Kh2 f5 6 Kg2 Ke5 7 Kf3 Kd4 8 Ke2 Ke4 9 f3+ Kf4 10 Kf2 g6 11 Ke2 Kg3 12 Ke3 f4+ 13 Ke2 Kg2 14 Kd2 Kxf3 15 Kd3 Kg2 16 h4 gxh4 17 Kc3 f3 18 Kb3 f2 19 Ka3 f1Q 20 Kb4 Qc1 21 Kb3 Qc5 22 Kb2 Qc4 23 Kb1 Qe2 24 Ka1 h3 25 Kb1 h2 26 Ka1 h1Q# 0:1


Fundemental Positions and Color Codes


Farbcode


Color codes for the Representation of Positional Types without taking care of the right to move


List of examples